Crkva Kovacica Crkva Kovacica - 1 year ago 60
Javascript Question

How to fix this program so it searches only my name?

I am learning JavaScript and i built this program, that searches for instances of the letter E within the

, and than stores letter by letter to an
but now when it finds a similar instance of the letter E it also outputs the similar instance, in this case i have Eddie, and Eric. And i don't want it to output the similar instance which is Eric in this case. I know there is a hacky way to do it, something like
if(nameYouFound !== "myName")
. But i don't like it... On the website where i learned this, it says there is built in JavaScript,
method that can help. Do you know what is the method that can solve the problem?

Please don't answer with JQuery, i am trying to get better at

Here is the code snippet:

/*jshint multistr:true */
var text, myName, hits, i, j;
text = "Hello, there, how are you feeling Eddie hope you are ok, ok Eric";
myName = "Eddie";
hits = [];
for (i = 0; i < text.length; i++) {
if (text[i] === "E") {
for (j = i; j < (myName.length + i); j++) {

if (hits.length == 0) {
alert("Your name was not found!")
} else {

Answer Source

You can use the built-in indexOf() method for strings.

var text = "Hello, there, how are you feeling Eddie hope you are ok, ok Eric";
var myName = "Eddie";
var hits = [];
var startIndex = text.indexOf(myName);
if (startIndex !== -1) { // myName exists in text
    for (var i = startIndex; i < startIndex + myName.length; ++i) {
else {
    // Do whatever you want like.. 
    console.log("Not Found!")
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