Pradana - 1 month ago 9

C++ Question

I currently have this function:

`double GrabNumber() {`

double x;

cin >> x;

while (cin.fail()) {

cin.clear();

cin.ignore(numeric_limits<streamsize>::max(), '\n');

cout << "You can only type numbers!\nEnter the number: ";

cin >> x;

}

return x;

}

Its purpose is to check if

`x`

`cin >> x`

It's called during this function:

`void addition() {`

cout << "\nEnter the first number: ";

double a = GrabNumber();

cout << "Enter the second number: ";

double b = GrabNumber();

// rest of code

When I type for example "6+" when it tells me to enter the first number, it accepts it but immediately goes to the second line and calls it an error where I haven't even entered my input.

I assume this is because the first input only accepts "6" while "+" goes to the second input returning an error. Therefore, there must be an issue with the parameters of

`while`

Answer

If your input is immediately successful, you don't ignore the rest of the line, which ends up into the next input. This can be fixed by simply duplicating the `cin.ignore`

call.

```
double GrabNumber() {
double x;
cin >> x;
cin.ignore(numeric_limits<streamsize>::max(), '\n'); // <--
while (cin.fail()) {
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
cout << "You can only type numbers!\nEnter the number: ";
cin >> x;
}
return x;
}
```

I'll leave DRYing this code as an exercise ;)