Python list out of function

Question

I Need

['1', '2', '3']

to become this

[1, 2, 3]

This is my actual code:

def chain_a_list_int(p_chain :str):

   tab_chain=[] # [str]

   tab_int=[] # [int] (list to return)



   tab_chain = p_chain.split(",")

   tab_chain = [int(i) for i in tab_chain]

   tab_int.append(tab_chain)

   return tab_int

and return it to use it like that:

chain_a_list_int(input("enter the number to conserve: "))

but it give me this error when i print it out of the function:

<function chain_a_list_int at 0x000000000349FEA0>

when i try to print i use this:

 print(chaine_a_liste_entier)

when i print

tab_int

in the function it work pretty well but it's not when i'm out of it...

print(tab_int)

Result...

[1, 2, 3]

Answer 1

That's not an error, but an indication that Python doesn't think that you have asked it to call chain_a_list_int. The minimal tweak to your code is:

the_list = chain_a_list_int(input("enter the number to conserve: "))
print(the_list)

or

print(chain_a_list_int(input("enter the number to conserve: ")))

A reference to the name of the function chain_a_list_int, without a ( after it, does not actually cause the function's code to run. This distinction will be useful to you later on — for now, make sure any time you type the name of a function, you put a parenthesized expression after that name. (If @ForceBru posts an answer, you'll see a counterexample :) .)

Python list out of function

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