Jesh Kundem - 1 year ago 338

Python Question

I have couple of questions

Say I have a numpy array

`a = np.array([0,1,2,3,4,31])`

a0 = a[0]

a1 = a[1]

a2 = a[2]

a3 = a[3]

a4 = a[4]

a5 = a[5]

print hex(a4), hex(a5)

gives me

`0x4L 0x1F`

same for a0, a1, a2, a3,a5. I know the L is because of the numpy array.

Now how would I get 0x04 and not 0x4.

My required outcome is

`'0x1F0403020100'`

My required answer should start with 0x -- the hex values of a5, a4, a3, a2, a1, a0 - without the OX. The required output is a string. I can do the bit manipulation, if I have the zero. But not without it.

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Answer Source

You can try this workaround. An element wise `hex`

conversion and a later `join`

. `'0x'`

is added to the start of the string:

```
>>> a = np.array([0,1,2,3,4,31])
>>> '0x' + ''.join('{:02X}'.format(i) for i in reversed(a))
'0x1F0403020100'
```

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