user1934428 - 1 year ago 49

Ruby Question

(I already wrote a solution to the problem below, but would like to ask whether someone could suggest a cleaner solution, more being in the "Spirit" of Ruby).

PROBLEM: I have an (ordered) set of needles, an (ordered) set of elements in a haystack, and a predicate which takes a needle and a haystack element and yields true or false. The task is to find the first needle where there is some haystack element where the predicate is true, and then returns the haystack element. We are not interested in the needle. The needles and the haystack is represented as an Array.

For example, if

`needles = [17,3,7,121]`

haystack = [40,30,70]

and the predicate is

`def p(needle, hay)`

hay % needle == 0

end

the result should be 30, because for needle 17, no element in haystack fulfils the predicate, but for needle 3, the second element (30) does.

Here is my implementation:

`found = nil`

needles.find do |n|

found = haystack.find { |he| p(n,he) }

break if found

end

What I find a bit unnatural is that I basically throw away the result of the outer

`find`

`found`

`found`

`found = ......`

Any ideas?

Answer

The important thing to note is that it's the `haystack`

element you want to find, not the `needle`

. Therefore, this variable needs to be the one in your outermost loop.

It would then by more idiomatic to use Enumerable#any? to check for the presence of needles which satisfy the predicate, since you really only care about the `true`

/`false`

return value.

The end result is:

```
haystack.find do |he|
needles.any? { |needle| p(needle, he) }
end
```

**EDIT:** I misunderstood the question slightly, sorry. If we are *ordering* the needles, and finding the first haystack which satisfies the predicate the "highest-ordered" needle, then we could do:

```
haystack
.select { |he| needles.any? { |needle| p(needle, he) } }
.min_by { |he| needles.index { |needle| p(needle, he) } }
```

Or as an alternate (more efficient) solution, how about:

```
haystack.min_by do |he|
needles.index { |needle| p(needle, he) } || Float::INFINITY
end
```

This funny use of `Float::INFINITY`

is used in case no `needles`

match the condition for the `haystack`

element, in which case the `index`

method returns `nil`

.

Source (Stackoverflow)