Claudia - 5 days ago 4x

C Question

Problem:1

In this code if I search a number which is not in array it should display

`Value not found`

`Found value in element -5`

`#include<stdio.h>`

#define SIZE 100

size_t linearSearch(const int array[], int key, size_t size);

int main(void)

{

int a[SIZE];

size_t x;

int searchKey;

size_t element;

for(x=0; x<SIZE; ++x){

a[x] = 2*x;

}

for(x=0; x<SIZE; ++x){

if(x%10 == 0){

puts("");

}

printf("%5d", a[x]);

}

puts("\n\nEnter integer search key:");

scanf("%d", &searchKey);

// attempt to locate searchKey in array a

element = linearSearch(a, searchKey, SIZE);

// display results

if(element != -1){

printf("Found value in element %d", element);

}

else{

puts("Value not found");

}

}

size_t linearSearch(const int array[], int key, size_t size)

{

if(size<0){

return -1;

}

if(key == array[size-1]){

return size-1;

}

return linearSearch(array, key, size-1);

}

Problem:2

I can't understood how

size_t linearSearch(const int array[], int key, size_t size)

function working specially these line

`if(key == array[size-1]){`

return size-1;

return linearSearch(array, key, size-1);

Answer

As everyone said that you have a little mistake that is, you should write `if(size==0)`

not `if(size<0).`

let me explain what's going on recursively in `linearSearch()`

function

```
size_t linearSearch(const int array[], int key, size_t size)
{
if(size == 0){
return -1;
}
else
if(key == array[size-1]){
return size-1;
}
else{
return linearSearch(array, key, size-1);
}
}
```

Suppose you gave an input `198`

as searchkey.
When you calling `linearSearch()`

function by the statement

```
element = linearSearch(a, searchKey, SIZE);
```

you are passing reference to `array[], searchKey 198, and Size 100`

as argument.

In linearSearch function first if statement `if(size==0)`

checks if the size is equal to zero if not then else if statement runs.

in else if statement `If(198 == array[100-1])`

condition is checked.
and we see `198`

is present in `array[99]`

so the else if condition is true thus linearSearch function return the 99 as result.

Now lets see what happend if you input `55`

which is not in the array list.
if(size==0) is not true so program will skip it and will go to the next statement.
`if(55 == array[100-1]`

will be checked as its not true then `linearSearch(array, 55, 100-1)`

will be called. again `if(55==array[99-1])`

will be checked.
at some point size will become 0. and the first `if(size==0)`

statement will execute.

Source (Stackoverflow)

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