user3700852 - 15 days ago 5x

Python Question

`n = int(input("Enter the number of elements in the array (2-200,000):"))`

a = [int(x) for x in input("Enter all numbers of the sequence with only non-negative intergers not exceeding 100,000:").split()]

c = list()3

for i in range(0,n):

for j in range (1,n):

if a[i] != a[j]:

m = a[i]*a[j]

c.append(m)

else:

continue

print(max(c))

This code works. However, I want to define a function to automatically calculating the max product from the 5th line in the code shown below.

`def MaxPairwiseProduct(n,a,c):`

for i in range(0,n):

for j in range (1,n):

if a[i] != a[j]:

m = a[i]*a[j]

c.append(m)

else:

continue

Product = max(c)

return Product

n = int(input("Enter the number of elements in the array (2-200,000):"))

a = [int(x) for x in input("Enter all numbers of the sequence with only non-negative intergers not exceeding 100,000:").split()]

c = list()

MaxPairwiseProduct(n,a,c)

I re-write the function but it does not work. It reveals "IndentationError: expected an indented block"

Answer

```
def MaxPairwiseProduct(n,a,c):
for i in range(0,n):
for j in range (1,n):
if a[i] != a[j]:
m = a[i]*a[j]
c.append(m)
else:
continue
Product = max(c)
return Product
n = int(input("Enter the number of elements in the array (2-200,000):"))
a = [int(x) for x in input("Enter all numbers of the sequence with only non-negative intergers not exceeding 100,000:").split()]
c = list()
print(MaxPairwiseProduct(n,a,c))
```

Source (Stackoverflow)

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