K DawG K DawG - 1 year ago 338
Python Question

ValueError: malformed string when using ast.literal_eval

It is widely known that using

is a potential security risk so the use of
is promoted

However In python 2.7 it returns
ValueError: malformed string
when running this example:

>>> ast.literal_eval("4 + 9")

Whereas in python 3.3 this example works as expected:

>>> ast.literal_eval('4+9')

Why does it run on python 3 and not python 2? How can I fix it in python 2.7 without using the risky

Answer Source

The reason this doesn’t work on Python 2 lies in its implementation of literal_eval. The original implementation only performed number evaluation for additions and subtractions when the righth operand was a complex number. This is syntactically necessary for complex numbers to be expressed as a literal.

This was changed in Python 3 so that it supports any kind of valid number expression to be on either side of the addition and subtraction. However, the use of literal_eval is still restricted to additions and subtractions.

This is mostly because literal_eval is supposed to be a function that turns a single constant literal (expressed as a string) into a Python object. Kind of like a backwards repr for simple built-in types. Actual expression evaluation is not included, and the fact that this works with Python 3 is just a nice-to-have side effect from its implementation.

In order to evaluate actual expressions, without having to use eval (which we don’t want to), we can write our own expression evaluation algorithm that operates on the AST. This is pretty simple, especially for simple arithmetic operations on numbers (for example to build your own calculator etc.). We simply parse the string into an AST and then evaluate the resulting tree by looking at the different node types and applying the correct operation.

Something like this:

import ast, operator

binOps = {
    ast.Add: operator.add,
    ast.Sub: operator.sub,
    ast.Mult: operator.mul,
    ast.Div: operator.div,
    ast.Mod: operator.mod

def arithmeticEval (s):
    node = ast.parse(s, mode='eval')

    def _eval(node):
        if isinstance(node, ast.Expression):
            return _eval(node.body)
        elif isinstance(node, ast.Str):
            return node.s
        elif isinstance(node, ast.Num):
            return node.n
        elif isinstance(node, ast.BinOp):
            return binOps[type(node.op)](_eval(node.left), _eval(node.right))
            raise Exception('Unsupported type {}'.format(node))

    return _eval(node.body)

As you can see, this implementation is pretty straightforward. Of course it does not support more complex stuff like exponentiation and some unary nodes yet, but it’s not too difficult to add that. And it works just fine:

>>> arithmeticEval('4+2')
>>> arithmeticEval('4*1+2*6/3')

You could even introduce more complex things later (for example function calls for things like sin()).

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