Darwin Tech Darwin Tech - 11 months ago 69
AngularJS Question

Angular UI router handling 404s

I have an app with a service which wraps my API calls:

var ConcernService = {
get: function (items_url, objId) {
var defer = $q.defer();
$http({method: 'GET',
url: api_url + items_url + objId}).
success(function (data, status, headers, config) {
}).error(function (data, status, headers, config) {
console.log('ConcernService.get status',status);
return defer.promise;

and I'm using UI-Router to transition between states:


.config( function ($stateProvider, $urlRouterProvider) {


$stateProvider.state('project', {
url: '/project/:projectId/',
resolve: {
project: function ($stateParams, ConcernService) {
return ConcernService.get('projects/', $stateParams.projectId);
views: {

I'm moving from using the normal Angualr router and I'm having difficulty understanding how to implement 404s. I can see the
throwing the
status as rejected, but how do I catch this in the state router?

Any help much appreciated.

Answer Source

The otherwise() rule is only invoked when no other route matches. What you really want is to intercept the $stateChangeError event, which is what gets fired when something goes wrong in a state transition (for example, a resolve failing). You can read more about that in the state change event docs.

The simplest implementation for what you're trying to do would be something like this:

$rootScope.$on('$stateChangeError', function(event) {

Also, since $http itself is built on promises (which resolve resolves), your ConcernService method can be simplified down to a one-liner (I realize you expanded it for debugging purposes, but you could have just as easily chained it, just FYI):

var ConcernService = {

  get: function (items_url, objId) {
    return $http.get(api_url + items_url + objId);