Pietro Lazzarotto - 1 year ago 64

C++ Question

My program takes a vector of long doubles as input (

`vector<long double>`

Everything works fine untill I try these two numbers: 1.18973e+4932 and 1.18973e+4932.

It outputs the following:

`<2: 1.18973e+4932 1.18973e+4932 >`

Min: 1.18973e+4932

Max: 1.18973e+4932

Range: 0

Midrange: inf

Median: inf

Mean: inf

Variance: inf

StdVariance : inf

After some researches, I found out that the value is exceeding the space in memory available for its own type.

Answer Source

Scaling ** might** help depending on what the compiler chooses to do with your code:

```
$ cat s.cpp
#include <iostream>
int main()
{
long double v = 1.18973e+4932L;
std::cout << "Midrange: " << (v + v) / 2 << '\n';
std::cout << "Midrange again: " << (v/2 + v/2) << '\n';
return 0;
}
$ g++ s.cpp -Wall -O2 -o s
$ ./s
Midrange: inf
Midrange again: 1.18973e+4932
```

You can also avoid calculating anything when the sample `min`

and `max`

are equal, and just set *mean*, *midrange* and *median* equal to either value, and *range*, *variance* and *standard deviation* to `0.0`

without messing around any further.