Toyi Hill - 8 days ago 5

Ruby Question

I understood how the formula for Fibonacci works but not the recursion part.

For example, fib(4) will call for fib(3) + fib(2), then what? How does the method determines the value of fib(3) and fib(2)? I am a beginner in Ruby so please excuse me for asking a noob question.

`def fib num`

return num if(0..1).include? num

fib(num-1) + fib(num-2)

end

Answer

Recursion works by calling itself again and again until the 'break point' happens. Fib(4) calls for fib(3) and fib(2), fib(3) calls for fib(2) and fib(1)... method has given the value of fib(1) and fib(0) as 1.

Let me try to explain it visually:

```
> fib(4) = fib(3) + fib(2)
> => fib(2) + fib(1) + fib(1) + fib(0)
> => fib(1) + fib(0) + 1 + 1 + 1
```

Source (Stackoverflow)

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