Chinu Chinu - 1 year ago 63
AngularJS Question

How to escape 1st index in AngularJS dropdown?

I have dynamically created dropdown. Here is my code and output -

<select class="form-control"
ng-init=" = conditions.fieldId"
ng-change="getOptionsChoice(conditions, conditions.fieldId)"
ng-options=" as option.placeholder for option in attribute_values">


<select ng-options=" as option.placeholder for option in attribute_values" ng-change="getOptionsChoice(conditions, conditions.fieldId)" ng-model="conditions.fieldId" name="conditon_dropdown" ng-init=" = conditions.fieldId.toString()" class="form-control ng-pristine ng-untouched ng-valid ng-not-empty">
<option value="?" selected="selected"></option>
<option label="Size" value="number:1">Size</option>
<option label="Color" value="number:2">Color</option>
<option label="Fit" value="number:3">Fit</option>
<option label="Rise" value="number:4">Select Rise</option>

Here is automatically created
<option value="?" selected="selected"></option>
I want to selected my default first option
<option label="Size" value="number:1">Size</option>

Edit: I have written
$scope.conditions.fieldId = 1
this is working fine. But my option value dynamic. It may be string or integer. How to manage this in HTML without controller?

Answer Source

Assign your first element of Array to the ng-model element, like this

If your array is attribute_values

$scope.ngModelElement = $scope.attribute_values[0].fieldId;

And define ng-model element in controller with $scope

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