freedev - 2 months ago 6x

Scala Question

I'm playing with scala streams.

Here is the stream of all integers starting from a given number.

I have added a

`println`

`def from(n: Int): Stream[Int] = n #:: from({ println(n); n + 1 })`

val nats = from(0) //> nats : Stream[Int] = Stream(0, ?)

nats.take(4).toList //> 0

//| 1

//| 2

//| 3

//| res0: List[Int] = List(0, 1, 2, 3, 4)

As expected, this is the output of my scala worksheet. Then I have created the stream of all prime numbers.

`def sieve(s: Stream[Int]): Stream[Int] = {`

s.head #:: sieve(s.tail.filter({ println( "---" ); _ % s.head != 0 }))

} //> sieve: (s: Stream[Int])Stream[Int]

val primes = sieve(from(2))//> primes : Stream[Int] = Stream(2, ?)

primes.take(4).toList //> 2

//| ---

//| 3

//| 4

//| ---

//| 5

//| 6

//| ---

//| res1: List[Int] = List(2, 3, 5, 7)

Here comes the question. I have made what in my opinion should be a little change, adding the

`x`

`_`

`def sieve(s: Stream[Int]): Stream[Int] = {`

s.head #:: sieve(s.tail.filter(x => { println("---"); (x % s.head) != 0 }))

} //> sieve: (s: Stream[Int])Stream[Int]

val primes = sieve(from(2))//> primes : Stream[Int] = Stream(2, ?)

primes.take(4).toList //> 2

//| ---

//| 3

//| ---

//| 4

//| ---

//| ---

//| 5

//| ---

//| 6

//| ---

//| ---

//| ---

//| res1: List[Int] = List(2, 3, 5, 7)

I don't understand why all these repetitions.

What's wrong in using the explicit parameter?

Answer

The difference is because `{ println( "---" ); _ % s.head != 0 }`

is short for `{ println( "---" ); x => x % s.head != 0 }`

rather than `{ x => println( "---" ); x % s.head != 0 }`

.

In the first case you first call `println`

and then return the function, so `---`

is printed once per `filter`

call; in the second it's once per `filter`

call per element of the stream being filtered (and because `sieve`

is recursive and filters the stream again, you end up with multiple `---`

for each element of the output).

Source (Stackoverflow)

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