Marc V Marc V - 2 years ago 200
jQuery Question

Why does jQuery throw the error `fadeOut is not a function'?

I am using jQuery and put this code in my javascript:

function HideMe(itemID) {
var myDiv = 'item_' + itemID;

But its giving me this error: fadeOut is not a function.

Answer Source

Do you have another javascript library on that page? It seems you have the hide function, and the $ defined (prototype, for example, also has an hide function).
If that is the case, try:

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