Ahmed Saleh - 1 month ago 5x

C++ Question

Given a large array of integers and a window of size 'w', find the current maximum in the window as the window slides through the entire array.

I have made two for loops, the first loops is working correctly but the inner loop doesn't move correctly based on different window sizes.

I tried to draw it on paper, but I still can't get a formula for the inner loop

`int main() {`

vector<int> arr = { -4, 2, -5, 3, 6 };

int window = 3;

for (int i = 0; i < arr.size() - window; i++)

{

int max = arr[i];

for (int j = i + 1; j < i + window; j++)

{

cout << " i = "<<i << "j = " << j << endl;

if (max < arr[j])

max = arr[j];

}

cout << max << " " << endl;

}

Answer

Your inner loop is correct. It's your outer loop's that's off by 1, it should be:

```
for (int i = 0; i <= arr.size() - window; i++)
```

With your array of 5 elements and the window size of 3, the last window is `array[2]`

through `array[4]`

. `arr.size()`

is 5. `window`

is 3. 5-3=2, and you need to still iterate for that window starting position.

Source (Stackoverflow)

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