Willy David Jr Willy David Jr -3 years ago 115
C# Question

Using LINQ to get all property with the exact same value?

I have a list of data like this:

Prod1: Id=1, Name="Book", Active=true
Prod2: Id=2, Name="Book", Active=false
Prod3: Id=3, Name="Book", Active=true
Prod4: Id=4, Name="Laptop", Active=true
Prod5: Id=5, Name="Laptop", Active=true
Prod6: Id=6, Name="Laptop", Active=true


What I want to perform is to get reduced list like this:

Prod1: Id=4, Name="Laptop", Active=true


What I am trying to do is that I need to select all products group by its Name, and return all that has true. Since Book has one false, it should not return Book.

I've tried this one:

lstProducts = lstProducts
.Where(x =>
lstProducts
.All(c => c.Name == x.Name && c.Active == true))
.GroupBy(c => c.Name).Select(c => c.First())
.ToList();


But its returning zero results. If I do a
where clause where Active == true
, its getting a Book product, which shouldn't since all of its Active should be true in order to get it.

Answer Source

What you are looking for is to first group all items by their Name, then filter only those that have all true for Active and last retrieve the first item for each group:

var result = lstProducts.GroupBy(item => item.Name)
                        .Where(group => group.All(item => item.Active)
                        .Select(group => group.First());

If you want to ensure some ordering for the group, as in your example then:

var result = lstProducts.GroupBy(item => item.Name)
                        .Where(group => group.All(item => item.Active)
                        .Select(group => group.OrderBy(item => item.Id).First());
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