Adler Weber - 3 months ago 13

Python Question

Here is the code for a calculator in Python:

`import time`

#Returns the sum of num1 and num2

def add(num1, num2):

return num1 + num2

#Returns the difference of num1 and num2

def subtract(num1, num2):

return num1 - num2

#Returns the quotient of num1 and num2

def divide(num1, num2):

return num1 / num2

#Returns the product of num1 and num2

def multiply(num1, num2):

return num1 * num2

#Returns the exponentiation of num1 and num2

def power(num1, num2):

return num1 ** num2

import time

def main ():

operation = input("What do you want to do? (+, -, *, /, ^): ")

if(operation != "+" and operation != "-" and operation != "*" and operation != "/" and operation != "^"):

#invalid operation

print("You must enter a valid operation")

time.sleep(3)

else:

var1 = int(input("Enter num1: ")) #variable one is identified

var2 = int(input("Enter num2: ")) #variable two is identified

if(operation == "+"):

print (add(var1, var2))

elif(operation == "-"):

print (subtract(var1, var2))

elif(operation == "/"):

print (divide(var1, var2))

elif(operation == "*"):

print (multiply(var1, var2))

else:

print (power(var1, var2))

main()

input("Press enter to exit")

exit()

About 30 minutes ago I found my old Python folder and took a look at all my basic scripts from 8+ months ago. I found my calculator mini-script and thought it would be fun to recreate it in as few lines as possible (I'm just now learning lambda). Here's what I have:

`main = lambda operation,var1,var2: var1+var2 if operation=='+' else var1-var2 if operation=='-' else var1*var2 if operation=='*' else var1/var2 if operation=='/' else 'None'`

print(main(input('What operation would you like to perform? [+,-,*,/]: '),int(input('Enter num1: ')),int(input('Enter num2: '))))

input('Press enter to exit')

I know this is a personal question based off of my specific situation, but I would appreciate any help making it shorter. Is there a way to make it more Pythonic? Am I using lambda correctly? Is there a way to handle errors in my shortened version? Any help would be appreciated. I'm very new to this. Thanks!

Answer

In order to simplify the code, I will suggest to:

*Create a function to perform operation taking the help of dictionary*.Note: I desrcide the alternative with

`lambda`

function based on requirement mentioned by user. Personally I would use`operator`

Using

`operator`

:`import operator def perform_operation(my_operator): return { '+': operator.add, '-': operator.sub, '*': operator.mul, '/': operator.truediv, # "operator.div" in python 2 '^': operator.pow, }.get(my_operator, '^') # using `^` as defualt value since in your # "else" block you are calculating the `pow``

Using

`lambda`

:`def perform_operation(my_operator): return { '+': lambda x, y: x + y, '-': lambda x, y: x - y, '*': lambda x, y: x * y, '/': lambda x, y: x / float(y), '^': lambda x, y: x ** y, }.get(my_operator, '^') # using `^` as defualt value since in your # "else" block you are calculating the `pow()``

Sample run:

`>>> perform_operation('/')(3, 5) 0.6`

*PS: Looking at the defination you would have got the idea why using*`operator`

is more pythonic than`lambda`

*Update your*as:`else`

block to make a call to it`var1 = int(input("Enter num1: ")) var2 = int(input("Enter num2: ")) perform_operation(operation)(var1, var2) # Making call to function created above # THE END - nothing more in else block`

*Simplify your*with:`if`

condition`if operation not in ["+", "-", "*", "/", "^"]: # invalid operation`