Mr.Roboto - 1 month ago 5

Python Question

I have a list of tuples:

`[ ('A',100), ('B',50), ('A',50), ('B',20), ('C',10) ]`

I am trying to sum up all numbers that have the same letter. I.e. I want to output

`[('A', 150), ('B', 70), ('C',10)]`

I have tried using set to get the unique values but then when I try and compare the first elements to the set I get

`TypeError: unsupported operand type(s) for +: 'int' and 'str'`

Any quick solutions to match the numbers by letter?

Answer

Here is a one(and a half?)-liner: group by letter (for which you need to sort before), then take the sum of the second entries of your tuples.

```
from itertools import groupby
from operator import itemgetter
data = [('A', 100), ('B', 50), ('A', 50), ('B', 20), ('C', 10)]
res = [(k, sum(map(itemgetter(1), g)))
for k, g in groupby(sorted(data, key=itemgetter(0)), key=itemgetter(0))]
print(res)
// => [('A', 150), ('B', 70), ('C', 10)]
```

The above is O(n log n) — sorting is the most expensive operation. If your input list is truly large, you might be better served by the following O(n) approach:

```
from collections import defaultdict
data = [('A', 100), ('B', 50), ('A', 50), ('B', 20), ('C', 10)]
d = defaultdict(int)
for letter, value in data:
d[letter] += value
res = list(d.items())
print(res)
// => [('B', 70), ('C', 10), ('A', 150)]
```

Source (Stackoverflow)

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