Jake2k13 Jake2k13 - 6 months ago 47
C++ Question

Bool type True and False

I was playing around with the Bool type (Boolean Variable) and typed this:

#include <iostream>

int main(void)
using std::cout;
using std::cin;
using std::endl;

bool $ok = false & true;

if($ok == true)
cout << "The value is True." << endl;
else if($ok == false)
cout << "The value is false." << endl;

return 0;

I know the differences between using the bitwise operator
and the logical operator
, but I do not see how this produces a false (0) value. I know if I swapped the bitwise operator and used a
the expression
would cause it to evaluate to
. Can someone explain why this:

bool $ok = false & true;

evaluates to false?

Answer Source

false=0(0x00000000) true=1(0x00000001)

Now when we do bitwise and operator of (false & true)---(0&1=0).

         &  0x00000001

Hence the result is 0(0x00000000)

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