DS_ - 1 year ago 90
Javascript Question

# Sort Objects in Array with duplicate values

So I've got an array of objects...

``````var array = [
{'name':'Jack', 'age':'30', 'weight':'200'},
{'name':'Ted', 'age':'27', 'weight':'180'},
{'name':'Ed', 'age':'25', 'weight':'200'},
{'name':'Bill', 'age':'30', 'weight':'250'}
]
``````

...which I know I can sort in ascending order based on their age using...

``````array.sort(function(a, b) {
return (a.age) - (b.age);
});
``````

Given all this, how can sort by a second parameter only if the ages of two different objects are the same? For instance, in my object, both "array.name = Jack" and "array.name = Bill" have the same age of 30. How can I go in and make absolutely sure that Jack will come before Bill because Jack has a lower weight?

Answer Source

You could add another sort criteria with chaining with logical OR `||` operator.

With same age, the difference is zero (a falsey value) and the second part is evaluated.

This method allows to add more sort criteria.

``````var array = [{ name: 'Jack', age: '30', weight: '200' }, { name: 'Ted', age: '27', weight: '180' }, { name: 'Ed', age: '25', weight: '200' }, { name: 'Bill', age: '30', weight: '250' }];

array.sort(function (a, b) {
return a.age - b.age || a.weight - b.weight;
});

console.log(array);``````
``.as-console-wrapper { max-height: 100% !important; top: 0; }``

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