alx9r - 6 months ago 64

PowerShell Question

Powershell's array notation has rather bizarre, albeit documented, behavior for slicing the end of arrays. This section from the official documentation sums up the bizarreness rather well:

Negative numbers count from the end of the array. For example, "-1"

refers to the last element of the array. To display the last three

elements of the array, type:

`$a[-3..-1]`

However, be cautious when using this notation.

`$a[0..-2]`

This command does not refer to all the elements of the array, except

for the last one. It refers to the first, last, and second-to-last

elements in the array.

The following code confirms the bizarreness:

`$a = 0,1,2,3`

$a[1..-1]

Which indeed outputs this bizarre result:

`1`

0

3

So, the question is, what

Please tell me it's something better than this ugly mess:

`$a[1..($a.Count-1)]`

Edit:

Another way to describe what I'm looking for is this: The idiomatic Powershell equivalent of this python expression:

`a=1,2,3,4`

a[1:-1]

Which, of course, evaluates to

`(2,3)`

Answer

If you want to get *n* elements from the end of an array simply fetch the elements from *-n* to *-1*:

`PS C:\> `**$a = 0,1,2,3**
PS C:\> **$n = 2**
PS C:\> **$a[-$n..-1]**
2
3

**Edit:** PowerShell doesn't support indexing relative to both beginning *and* end of the array, because of the way `$a[$i..$j]`

works. In a Python expression `a[i:j]`

you specify `i`

and `j`

as the first and last index respectively. However, in a PowerShell `..`

is the range operator, which generates a sequence of numbers. In an expression `$a[$i..$j]`

the interpreter first evaluates `$i..$j`

to a list of integers, and then the list is used to retrieve the array elements on these indexes:

`PS C:\> `**$a = 0,1,2,3**
PS C:\> **$i = 1; $j = -1**
PS C:\> **$index = $i..$j**
PS C:\> **$index**
1
0
-1
PS C:\> **$a[$index]**
1
0
3

If you need to emulate Python's behavior, you *must* use a subexpression:

`PS C:\> `**$a = 0,1,2,3**
PS C:\> **$i = 1; $j = -1**
PS C:\> **$a[$i..($a.Length+$j-1)]**
1
2