gmesorio gmesorio - 3 months ago 116
AngularJS Question

Upload file to controller using typescript

I am using ASP.NET MVC 5 for the backend and Angular + Typescript for the frontend of a web application.
I am trying to upload a file to the server, but for some reason the controller is not getting the file as parameter (the parameter in the controller is null).

I share below the code.

Thanks in advance!

HTML:

<input id="filePath" name="filePath" type="file" accept="image/*" />
<a id="uploadImage" ng-click="ctrl.uploadFile()">Upload</a>


Typescript:

// controller class:
uploadFile(): void {
var filePathInput: any = $("#filePath");
if (filePathInput[0].files) {
var file: any = filePathInput[0].files[0];
var resource: any = this.service.uploadFile();
resource.save(file, (result: any) => {
if (!result || !result.success) {
alert("error");
} else {
alert("ok");
}
});
}
}

// service class:
uploadFile(): ng.resource.IResourceClass<IMyResource> {
return this.$resource("/MyController/UploadImage", null, { method: "POST" });
}


Backend Controller:

[HttpPost]
public JsonResult UploadImage([FromBody]HttpPostedFileBase file)
{
if (file == null || file.ContentLength == 0)
{
return NullParameterResponse();
}
else
{
file.SaveAs("/img/" + Path.GetFileName(file.FileName));
return SuccessResponse();
}
}

Answer

TransformRequest function: This makes your request to be sent as a FormData instead as a JSon object.

 formDataObject(data: any): any {
        var fd = new FormData();
        angular.forEach(data, function (value, key) {
            fd.append(key, value);
        });
        return fd;
    }

In your angular resource, define the save options and pass the transformRequest function you created earlier.

uploadChequeFile(): ng.resource.IResourceClass<IChequeLoanResource> {
        return this.$resource<IChequeLoanResource>("/Cheque/UploadChequeImage", null,
            {
                save: {
                    method: "POST",
                    transformRequest: this.formDataObject,
                    headers: { 'Content-Type': undefined, enctype: 'multipart/form-data' }
                }
            });
    }

In your controller, just call your save method from the resource passing your file.

var chequeFilePathInput: any = $("#chequeFilePath");
        if (chequeFilePathInput[0].files) {
            var resource: ng.resource.IResourceClass<services.IChequeLoanResource> = this.uLendService.uploadChequeFile();
            resource.save({ "files": chequeFilePathInput[0].files[0] }, (result: any) => {
                if (!result || !result.success) {
                    this.errorMessage = "Error al subir la imagen al servidor. Por favor contáctanos si el error persiste.";
                } else {
                    this.chequeLoan.cheque.filePath = result.message;
                    this.saveChequeLoan();
                }
            });
        } else {
            this.errorMessage = "La imagen del cheque es requerida.";
        }

Finally, your controller must receive the IList parameters (with the same name defined in your angular controller)

public JsonResult UploadChequeImage(IList<IFormFile> files)
    {
        try
        {
            if (files != null && files.Count > 0)
            {
                return CreateResponse(true, CreateFile(files[0], @"img\cheques"));
            }
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