AutomateStuff AutomateStuff - 4 months ago 10
Linux Question

Why is idle skipping over f = open('filename' , 'r')

I'm writing a program in python and I am having issues getting idle to read my file out. If I use improper syntax it tells me, so it is being read by the compiler but not printing it for the user. Any help would be appreciated. Here is my code.

#! python3.5.2

import sys

if input() == ('im bored'):
print('What season is it?')
if input() == ('summer'):
f = open('callfilesummer.txt', 'r')

Answer

You only put file into variable 'f', so you need to read it or work it with someway to show it.

import sys

if input() == ('im bored'):
    print('What season is it?')
    if input() == ('summer'):
       f = open('callfilesummer.txt', 'r')
       print f.read()
       f.close()

You can find more way how to work with files on this http://www.tutorialspoint.com/python/python_files_io.htm

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