okkhoy - 1 month ago 5x

Python Question

In python

`random`

`expovariate()`

Answer

jonrsharpe already kind of mentioned it, you can just let the function generate floating point numbers, and convert the output to integers yourself using int()

This

```
>>> import random
>>> [random.expovariate(0.2) for i in range(10)]
[7.3965169407177465, 6.950770519458953, 9.690677483221426, 2.1903490679843927, 15.769487400856976, 3.508366058170216, 2.1922982271553155, 2.591955678743926, 7.791150855029359, 22.180358323964935]
```

Should then be typed as

```
>>> import random
>>> [int(random.expovariate(0.2)) for i in range(10)]
[0, 10, 5, 15, 4, 0, 0, 4, 5, 4]
```

Another example

```
>>> import random
>>> [int(random.expovariate(0.001)) for i in range(10)]
[435, 64, 575, 2147, 1233, 1630, 1128, 899, 180, 1190]
```

The examples above use list comprehension to generate multiple results in one line. Can of course be reduced to

```
>>> import random
>>> int(random.expovariate(0.1)
5
```

Note that if you pass a higher number to `.expovariate()`

you are more likely to get smaller floating points as result, and when using `int()`

to convert the floats to integers, numbers that are between 0 and 1 will get converted to 0.

Source (Stackoverflow)

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