Muzahir Hussain Muzahir Hussain -4 years ago 49
C Question

Purpose of shm_open() and ftruncate()?

When we create a shared-Memory we use

function. According to my information
create a shared-memory region. And then we use
function to configure the size of shared-memory region.

Well how does
creates the memory region in the first place when it doesn't yet know the size? And if this is not the case and I am totally wrong, then please tell me the purpose of
Thanks in Advance!!!

Answer Source

The main point of shm_open is that you can open an existing memory area. However in the case that it didn't exist and you'd create it, shm_open behaves like open when creating a file; the newly created memory area has size of 0. From Linux manuals:


Create the shared memory object if it does not exist. The user and group ownership of the object are taken from the corresponding effective IDs of the calling process, and the object's permission bits are set according to the low-order 9 bits of mode, except that those bits set in the process file mode creation mask (see umask(2)) are cleared for the new object. A set of macro constants which can be used to define mode is listed in open(2). (Symbolic definitions of these constants can be obtained by including .)

A new shared memory object initially has zero length--the size of the object can be set using ftruncate(2). The newly allocated bytes of a shared memory object are automatically initialized to 0.

(emphasis mine)

Since shm_open does not take the size of newly created area as an argument (it'd complicate the system call / library call to add arguments for all sorts of cases), ftruncate() must used to change the size of an opened shared memory area from its initial size.

Of course you do not have to use ftruncate for a shared memory segment that is already properly created and resized elsewhere. Should you want to know its size, use fstat. See also shm_overview(7)

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download