Conrad Albrecht - 2 months ago 9x

C# Question

Seems like whenever I divide a negative int by a positive int, I need it to round *down* (toward -inf), not toward 0. But both C# and C++ round toward 0.

So I guess I need a DivideDownward() method. I can write it in a few lines with a test for negative and so on, but my ideas seem klugey. So I'm wondering if I'm missing something and if you have an "elegant" way to round negative division downward.

Answer

**WARNING: this post produces incorrect results for input with a=-1. Please see other answers. -Cam**

[c++]

This is probably what you meant by 'kludgey', but it's what I came up with ;)

```
int divideDown(int a, int b){
int r=a/b;
if (r<0 && r*b!=a)
return r-1;
return r;
}
```

In the if statement, I put r<0 - however I'm not sure if that's what you want. You may wish to change the if statement to

```
if (a<0 && b>0)
```

which would be consistent with your description "Seems like whenever I divide a **negative int by a positive int** ".

Source (Stackoverflow)

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