Hamid Reza AZ Hamid Reza AZ - 3 years ago 252
C++ Question

FFT and FFTShift of matlab in FFTW library c++

what is the exact equivalent of this MATLAB line code in C++ and using FFTW?


note: X is an array of 4096 double data.

now I use these lines of code in c++ and FFTW to compute fft

int n = 4096
fftw_complex *x;
fftw_complex *y;
x = (fftw_complex *)fftw_malloc(sizeof(fftw_complex) * n);
y = (fftw_complex *)fftw_malloc(sizeof(fftw_complex) * n);

for (int i=0; i<n; i++)
x[i][REAL] = MyDoubleData[i];
x[i][IMAG] = 0;

fftw_plan plan = fftw_plan_dft_1d(n, x, y, FFTW_FORWARD, FFTW_ESTIMATE);


It is just equivalent of FFT function in MATLAB.
Is there any equivalent function for FftShift in FFTW library?

Answer Source

The FFTW function calls you've provided would be the equivalent of fft(x,4096). If x is real, matlab knows to give you the conjugate symmetric FFT (I think). If you want to do this with FFTW, you need to use the r2c and c2r functions (real-to-complex/complex-to-real).

You have to do the shift yourself. You can do direct substitution (poor performance, but should be intuitive)

for (int i=0; i<n; i++)
    fftw_complex tmp;
    int src = i;
    int dst = (i + n/2 - 1) % n;


Alternatively use a couple memcpy's (and/or memmove's) or modify your input data

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