Grace Michelle Grace Michelle - 4 months ago 7x
PHP Question

PHP - Check Date Range

I have a table on database called

. The fields in this table are:
code | name | status | open_date | close_date
. The date format is

This is what I want: if today's date is out of date range in the database, the site won't display a form and a table column.

This is my code:

$sql5 = "select close_date from period"
. " where status='1'";
$result5 = mysqli_query($link, $sql5);
if (!$result5) {
die("<h3>SQL Error</h3>" . $sql5);
$row5 = mysqli_fetch_array($result5);

$date = date("Y/m/d");

if($date >= $row3['open_date'] && $date <= $row5['close_date']) {
<form action="manageInputPerwalian.php" method="POST">
<table align="center">
<td>MK Code:</td>
<td><input type="text" name="mkCode"/></td>
<td><input type="text" name="kp"/></td>
<td><input type="submit" value="SUBMIT"/></td>
<?php } ?>

<table border="1" style="width:100%">
<th>MK CODE</th>
<th>MK NAME</th>
<?php if($date >= $row3['open_date'] && $date <= $row5['close_date']) { ?>
<?php } ?>

But, either today's date is out of range or in the range, the form and the table column won't show up. What's wrong? Please explain your answer. Thanks


use strtotime() to convert the dates to timestamp and compare, as,

$openDateStr = strtotime($row3['open_date']);
$closeDateStr = strtotime($row5['close_date']);
$todayStr = strtotime(date("Y/m/d"));
if($todayStr >= $openDateStr && $todayStr <= $closeDateStr) {