arielnmz arielnmz - 8 days ago 9
Java Question

Java stream toArray() convert to a specific type of array

Maybe this is very simple but I'm actually a noob on Java 8 features and don't know how to accomplish this. I have this simple line that contains the following text:


"Key, Name"


and I want to convert that line into a String array, separating each value by the comma (,), however, I also want to trim every field before returning the final array, so I did the following:

Arrays.stream(line.split(",")).map(String::trim).toArray();


However, this returns an Object[] array rather than a String[] array. Upon further inspection, I can confirm that the contents are actually String instances, but the array itself is of Object elements. Let me illustrate this, this is what the debugger says of the returned object:

Object[]:
0 = (String) "Key"
1 = (String) "Name"


As far as I can tell, the problem is in the return type of the map call, but how can I make it return a String[] array?

Answer

Use toArray(value -> new String[value]) or toArray(String[]::new).

String[] strings = Arrays.stream(line.split(",")).map(String::trim).toArray(String[]::new);

This is actually a lambda expression for

.toArray(new IntFunction<String[]>() {
        @Override
        public String[] apply(int value) {
            return new String[value];
        }
    });

Where you are telling convert the array to a String array of same size.

From the docs

The generator function takes an integer, which is the size of the desired array, and produces an array of the desired size. This can be concisely expressed with an array constructor reference:

 Person[] men = people.stream()
                      .filter(p -> p.getGender() == MALE)
                      .toArray(Person[]::new);

Type Parameters:

A - the element type of the resulting array

Parameters:

generator - a function which produces a new array of the desired type and the provided length