Viktor Lindblad - 1 month ago 6x

Java Question

Is there any good way to search through a floats first four numbers and return every number seperately with int[]?

Example: the float 23,51 becomes the integer array, array[0]=2, array[1]=3, array[2]=5 and last arra[3]=1

My code:

`public void printNumber(float number){`

String string = String.valueOf(number);

while(!numbers.isEmpty()){

numbers.remove(0);

}

for(int i = 0; i < string.length(); i++) {

int j = Character.digit(string.charAt(i), 10);

this.number = new Number(j);

numbers.add(this.number);

System.out.println("digit: " + j);

}

}

I should mention that Number is a class that only returns a different picture based on the number the constructor is given and ofcourse the number itself.

numbers is an ArrayList

Answer

Convert `float`

to `String`

using fixed-point format, then go through its characters one-by-one, and ignore the decimal point.

If the number could also be negative, you need to pay attention to the sign in the `String`

output:

```
float v = 23.51F;
DecimalFormat df = new DecimalFormat("#");
df.setMaximumFractionDigits(8);
char[] d = df.format(v).toCharArray();
int count = 0;
for (int i = 0 ; i != d.length ; i++) {
if (Character.isDigit(d[i])) {
count++;
}
}
int[] res = new int[count];
int pos = 0;
for (int i = 0 ; i != d.length ; i++) {
if (Character.isDigit(d[i])) {
res[pos++] = Character.digit(d[i], 10);
}
}
```

**Important:** Be aware that `float`

s are inherently imprecise, so you may get a "stray" digit or two. For example, your example produces

```
[2 3 5 1 0 0 0 0 2 3]
```

with `2`

and `3`

at the end.

Source (Stackoverflow)

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