Accepting any number of inputs from scanf function

Question

I am trying to read an unknown number of inputs using

scanf

function.

int array[100];

int i = 0;



while((scanf("%d", &a[i])) != '\n')

 i++;



// Next part of the code

But this function is not going to next part of the code, seems like there is an infinite while loop.

How Do I solve this logical error? Is there any other alternatives to

scanf

like

sscanf

to read integers into an array?

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Answer 1

scanf returns the number of input items that have been successfully matched and assigned, thus it is reasonable to do:

while(scanf(...) == 1)

Now you want to be able to read multiple numbers, each defined on the new line. Then you could simply do this:

int array[100];
int i = 0;

while(i < 100 && scanf("%d\n", &array[i]) == 1)
    i++;

note that this reading will stop only if invalid input is entered (for example letter q) or when you input the end-of-input control code, which is Ctrl+Z (on Windows) or Ctrl+D (on Mac, Linux, Unix).

Accepting any number of inputs from scanf function

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