user525146 - 5 months ago 15x

SQL Question

I want to group by all the hours between 0 and 40 into one total sum.

41 - 50 into one total sum and 50+ into another sum.

`select hours,`

sum(hours)

from employee

where hours between 0 and 40

group by hours;

The above query groups by the hours, so i have the results split by hours, like if I have 1, 2.3, 0.5, 35.5, 30 etc.

`1 403`

2.3 4.6

0.5 53

35.5 284

30 1230

But I want something like

`403+4.6+53+284+1230 = 1974.6`

How can I do it ?

Answer

`GROUP`

-ing based on `CASE`

```
select (case when hours between 0 and 40
then '0 - 40'
when hours between 41 and 50
then '41 - 50'
else
'50+'
end) as hours_range,
sum(hours)
from employee
group by (case when hours between 0 and 40
then '0 - 40'
when hours between 41 and 50
then '41 - 50'
else
'50+'
end);
```

Source (Stackoverflow)

Comments