I'm struggling to figure out how to dynamically create a date object for the most previous sunday at 12:00 AM
I was thinking I could get today's date and then subtract the current day of the week + 1 at which point I could just subtract the time of the day do get down to 12AM.
so far I have the current day of the week:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [gregorian components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
int weekday = [comps weekday];
No need to manually calculate seconds (which is dangerous anyway because of daylight saving etc.). The following should do exactly what you want:
NSDate *today = [NSDate date]; NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; [calendar setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en-US"]]; // force US locale, because other countries (e.g. the rest of the world) might use different weekday numbering NSDateComponents *nowComponents = [calendar components:NSYearCalendarUnit | NSWeekCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:today]; [nowComponents setWeekday:1]; //Sunday [nowComponents setHour:0]; // 12:00 AM = midnight (12:00 PM would be 12) [nowComponents setMinute:0]; [nowComponents setSecond:0]; NSDate *previousSunday = [calendar dateFromComponents:nowComponents];