Masroor_Shah Masroor_Shah - 3 months ago 9
PHP Question

Character Wise Advance search in AJAX and PHP?

I have done advance search which match character from front side. I want that it should match with middle and End of the word also or to everywhere in Database. How should i can d that my advance search code is here
PHP code........................



<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<style>
table {
width: 100%;
border-collapse: collapse;
}

table, td, th {
border: 1px solid black;
padding: 5px;
}

th {text-align: left;}
</style>
</head>

<body>
<?php
$servername="localhost";
$username="root";
$password="";
$conn=mysql_connect($servername,$username,$password);
if (!$conn) {
die('Could not connect: ' . mysqli_error($conn));
}

$in=$_GET['q'];
if(!ctype_alnum($in)){
echo "Data Error";
exit;
}

mysql_select_db('firstdb');
$sql="select name, id , age, sex from name where name like '$in%' or sex like '$in%' or age like '$in%' or id like '$in%'";
$display=mysql_query($sql,$conn);
echo "<table>
<tr>
<th>ID</th>
<th>Name</th>
<th>Age</th>
<th>Gender</th>
</tr>";
while( $row = mysql_fetch_assoc( $display ) ){
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['sex'] . "</td>";
echo "</tr>";
}
echo "</table>";

?>
</body>
</html>





JS code



<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script>
function user(str){
if(str.length==0)
{
document.getElementById("userhint").innerHTML = "";
return;
}
else {
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("userhint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET", "advanceSearch.php?q="+str, true);
xmlhttp.send();
}


}

</script>
</head>
<body>

<form>
<input type="text" onkeyup="user(this.value);" name="username" />
</form>
<br />
<div id="userhint"><b>User info will be listed here...</b></div>
</body>
</html>




Answer

done by little change in query

$sql="select name, id , age, sex from name where name like '%$in%' or sex like '$%in%' or age like '%%$in%' or id like '%$in%'";