antonio_zeus - 4 months ago 9

Python Question

I am hoping someone can point me in the right direction along with any documentation that can provide even more info than just the answer. Here we go, I have a list of strings:

`arr = ["abcd","abcdef","def","abcdef"]`

I want to turn that list into a list of lists so that the new element will be its order of appearance

`arr = [("abcd",1),("abcdef",1),("def",1),("abcdef",2)]`

the reason for this is because I would like to then sort that list by length of string, and in case any are of identical length, I can use the 2nd element of the list to know which one was first from my original list.

`when "abcdef" appears twice, it also contains 1 or 2 in its 2nd element`

hope that makes sense. thanks!

Answer

Simple and pythonic.

```
[(v, lst[:i].count(v)+1) for i,v in enumerate(lst)]
```

where `lst`

is your list.

```
>>> lst = ["abcd","abcdef","def","abcdef"]
>>> [(v, lst[:i].count(v)+1) for i,v in enumerate(lst)]
[('abcd', 1), ('abcdef', 1), ('def', 1), ('abcdef', 2)]
```

Source (Stackoverflow)

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