dotslash dotslash - 1 year ago 224
Java Question

Java `json_decode` (PHP) equivalent

I'm coming to Java from a PHP background, and am surprised to see that JSON to object conversion is so constrained. In all the Jackson tutorials I came across, it looks like the object to be read needs to be pre-defined. Thus, if my data is in, say, JSON API format, I need to write boilerplate code to strip out everything except the "data" part, and then somehow convert all the strings into objects one by one.

I really miss PHP's

function, which will read any JSON and give you a PHP object to play with. It also builds the necessary structure into the object, adding arrays and sub-objects as needed. Of course I understand that Java is a compiled language, but I'm wondering how this can be made easier.

Answer Source

As a strongly typed language Java often has less of these "just give it to me"-type of functionalities, but that doesn't mean they don't exist. Even Jackson can deserialize JSON without a predefined schema, giving you Maps and Lists instead of domain objects.

Just remember that if you're working on "real" projects, there are plenty of advantages from having the schemas defined. They weren't invented to annoy you, but to make sure that you can trust your data being in the correct form (or find out early if it's not).

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