Java Question
Printing numbers that exclude those that end with x
I want to print the numbers from 0-100, excluding those that are multiples of 7 and those that end with 7. I can do all except the ending with 7 part. Is there a charAt equivalent for int?
Done, thanks for the help!
class revision{
public static void main(String[] args){
for(int i = 0; i < 101; i++){
if(i % 7 != 0 && i % 10 != 7){
System.out.println(i);
}
}
}
}
Answer
Is there a charAt equivalent for int?
Sort of: There's the remainder operation you're already using, just with a different divisor: i % 10 != 7 will weed out numbers "ending with 7." (In decimal; if you wanted to do it in octal, it would be % 8; or in hex it would be % 16, etc. E.g., you're isolating the "ones" digit by doing a remainder with the number base.)
So:
class revision{
public static void main(String[] args){
for(int i = 0; i < 101; i++){
if(i % 7 != 0 && i % 10 != 7){
// ------------^^^^^^^^^^^^^^^
System.out.println(i);
}
}
}
}
Side note: In Java, the overwhelming convention is for class names to start with an upper-case character. So Revision rather than revision.
Source (Stackoverflow)