iamTony iamTony - 27 days ago 13
Javascript Question

Ajax form $_POST blank return data

var name = jQuery('[data-field="name"]').val();
var email = jQuery('[data-field="email"]').val();
var inumber = jQuery('[data-field="inumber"]').val();
var rnumber = jQuery('[data-field="rnumber"]').val();
var date = jQuery('[data-field="date"]').val();
var amount = jQuery('[data-field="amount"]').val();
var feedback = jQuery('[data-field="name"]').val();

var file_attach = new FormData(jQuery('input[name^="media"]'));
jQuery.each(jQuery('input[name^="media"]')[0].files, function(i, file) {
file_attach.append(i, file);
});
jQuery.ajax({
type: 'POST',
data: { func: "sendMail", name,email,inumber,rnumber,date,amount,feedback,file_attach},
url: 'billing-information-mailer.php',
cache: false,
contentType: false,
processData: false,
success: function(data){
console.log(data);
}
});


I'm trying to pass form info and attachment to a php file to send an email, initially I just went with $.post however I need to set processData to false so I shifted to $.ajax, currently my php file is sending an empty return. the only code in my php file is
print_r($_POST);


EDIT:

<input type="file" name="media" data-field="billing" id="vdnupload" name="vdnupload" placeholder="Proof of Payment">

Answer

The syntax of the object you're providing to the data property is incorrect as each item needs a key.

However a more pressing problem is that to upload a file you need to put all the data (file and input values) in to the FormData object and send that alone. Try this:

var formData = new FormData();     
$.each($('input[name^="media"]')[0].files, function(i, file) {
    formData.append(i, file);
});
formData.append('name', $('[data-field="name"]').val());
formData.append('email', $('[data-field="email"]').val());
formData.append('inumber', $('[data-field="rnumber"]').val());
formData.append('rnumber', $('[data-field="rnumber"]').val());
formData.append('date', $('[data-field="date"]').val());
formData.append('amount', $('[data-field="amount"]').val());
formData.append('feedback', $('[data-field="name"]').val());

$.ajax({
    type: 'POST',
    data: formData,
    url: 'billing-information-mailer.php',
    cache: false,
    contentType: false,
    processData: false,
    success: function(data){
        console.log(data);
    }
});

You could make this much, much simpler if you place a form element around all the inputs you want to include in the request. That way you can just provide a reference of that form to the FormData constructor and all values will be populated for you:

var formData = new FormData($('#myForm')[0]);