perogiex perogiex - 9 days ago 6
C++ Question

How to exclude lcov branches within a macro

I've got some logging macros in my code along the lines of:

#define LOG_MSG (pri, msg, ... ) \
if (pri > PriorityLevel ) \
printf( msg, ##\__VA_ARGS__);


I know I can use LCOV_EXCL_START, LCOV_EXCL_STOP or LCOV_EXCL_LINE to suppress a branch. But that only works if I add it every place I call LOG_MSG:


LOG_MSG(ERROR, "An Error has occurred\n");//LCOV_EXCL_LINE


I'd like to include that comment in the macro, but LCOV doesn't recognize it if I put it there. For example, this code still produces branches.

#define LOG_MSG (pri, msg, ... ) \
if (pri > PriorityLevel ) \
printf( msg, ##\__VA_ARGS__);//LCOV_EXCL_LINE


Is there a good way to suppress these branches in the macro itself?

Answer

Why not turn the macro into function ?

like:

template <typename ... Ts>
void LOG_MSG(int priority, const std::string& message, Ts&&...ts)
{
    if (priority > PriorityLevel)
        printf(message.c_str(), std::forward<Ts>(ts)...);
    // Or more appropriate stuff
}