If I have two numpy arrays and want to find the the non-intersecting values, how do I do it?
Here's a short example of what I can't figure out.
a = ['Brian', 'Steve', 'Andrew', 'Craig']
b = ['Andrew','Steve']
Given that none of the objects shown in your question are Numpy arrays, you don't need Numpy to achieve this:
c = list(set(a).symmetric_difference(b))
If you have to have a Numpy array as the output, it's trivial to create one:
c = np.array(set(a).symmetric_difference(b))
(This assumes that the order in which elements appear in
c does not matter. If it does, you need to state what the expected order is.)
P.S. There is also a pure Numpy solution, but personally I find it hard to read:
c = np.setdiff1d(np.union1d(a, b), np.intersect1d(a, b))