itjcms18 - 1 year ago 121

Python Question

If I have two numpy arrays and want to find the the non-intersecting values, how do I do it?

Here's a short example of what I can't figure out.

`a = ['Brian', 'Steve', 'Andrew', 'Craig']`

b = ['Andrew','Steve']

I want to find the non-intersecting values. In this case I want my output to be:

`['Brian','Craig']`

The opposite of what I want is done with this:

`c=np.intersect1d(a,b)`

which returns

`['Andrew' 'Steve']`

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Given that none of the objects shown in your question are Numpy arrays, you don't need Numpy to achieve this:

```
c = list(set(a).symmetric_difference(b))
```

If you have to have a Numpy array as the output, it's trivial to create one:

```
c = np.array(set(a).symmetric_difference(b))
```

(This assumes that the order in which elements appear in `c`

does not matter. If it does, you need to state what the expected order is.)

P.S. There is also a pure Numpy solution, but personally I find it hard to read:

```
c = np.setdiff1d(np.union1d(a, b), np.intersect1d(a, b))
```

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**