John John - 1 month ago 11
C++ Question

C++, order of computation for the following code

In the following code, im trying to build 2 arrays. The first one is an array given by the user, the second one is an array which has been sorted among other things, although kept short since the actual implementation is not nescessary :

int main()
int size = 0;
cout << "Please enter size: ";
cin >> size;
int array[size];
int newArray[size] = doSomething(array,&size);
return 0;
int* doSomething(int array[],int *size)
int newArray[size];
//do something with the array and store it in the newArray
return newArray;

So my question is this:

My teacher told me that most compilers work differently, and the order of some operations might differ among them.

At the line int newArray[size] = doSomething(array,&size); I am expecting the size variable to be changed inside doSomething before it is used to initialize newArray. Once the doSomething method is finished running, it should return an array (WHICH I ASSUME It IS JUST RETURNING THE ADRESS OF THE FIRST ELEMENT OF THE ARRAY, PLEASE CORRECT ME IF THIS IS WRONG). Once it returns I want to store that address into my newly array, where the variable size is used to initalize the array's size. This variable should be according to my logic, equal to the original size entered by the user +1. So if the user enters a size of 4, the size of newArray should be 5. Is this a good way of going about it, or would it produce unreliable results for different compilers?

For the purpose of this exercise, I can only use built in array and pointers. So I cannot use vectors. Furthermore, in this example, the newArray is one element larger, but the actual code has a size which is dynamic, and therefore might be different each time. I can therefore not hard code the +1 inside the declaration.

If this is wrong, can someone point me in the right direction and help me to find a way where I can pass a built in array (no vectors or array<>), modify the contents and size of it and then return that array and store it in a variable in the caller method?

Thank you very much


You have a problem here:

 cin >> size; 
 int array[size];

Unless you use new you can't do that. The compiler creates the array container before the program runs, so you can't give it a custom size once it is running.

You must allocate your array as a new object on the heap:

cin >> size;
int* array = new int[size];

Maybe this will point you in the right direction, but I have no idea exactly what classes you are trying to call as you haven't included all of your source code.

I edited my previous answer, because I believe you are trying to simply call an array of ints, not a class called "array". If you just want a C-style array of integers, the above example is how you do it properly.

Keep in mind once you are done using the data you should call

delete[] array;