I am looking for a comparison of two times in Python. One time is the real time from computer and the other time is stored in a string formatted like
ctime = time.strptime("%H:%M:%S") # this always takes system time
time2 = "08:00:00"
if (ctime > time2):
import datetime now = datetime.datetime.now() my_time_string = "01:20:33" my_datetime = datetime.datetime.strptime(my_time_string, "%H:%M:%S") # I am supposing that the date must be the same as now my_datetime = now.replace(hour=my_datetime.time().hour, minute=my_datetime.time().minute, second=my_datetime.time().second, microsecond=0) if (now > my_datetime): print "Hello"
The above solution was not taking into account leap second days (
23:59:60). Below is an updated version that deals with such cases:
import datetime import calendar import time now = datetime.datetime.now() my_time_string = "23:59:60" # leap second my_time_string = now.strftime("%Y-%m-%d") + " " + my_time_string # I am supposing the date must be the same as now my_time = time.strptime(my_time_string, "%Y-%m-%d %H:%M:%S") my_datetime = datetime.datetime(1970, 1, 1) + datetime.timedelta(seconds=calendar.timegm(my_time)) if (now > my_datetime): print "Foo"