Usama Sadiq Usama Sadiq - 3 months ago 42
Swift Question

didReceiveInvitation() is not being called in XMPPFramework and Swift 2

I am creating chatting application like Whatsapp.

I have successfully write the functionality of Text chat, Image, Audio, Video Transfer. Now I am creating the Multi user chat. After a long R&D I am asking this question. Please tell me what I am doing wrong in my code. I have followed all these tutorials but not luck

https://github.com/robbiehanson/XMPPFramework/issues/640

MUC How-to with XMPPFramework

Accepting chatroom invitation

Ok Below is my Code

1. After setting the STREAM successfully i set the XMPPMUC delegate for Invitation in goOnline Method



private func goOnline() {
let presence = XMPPPresence()
let domain = xmppStream.myJID.domain

if domain == "gmail.com" || domain == "gtalk.com" || domain == "talk.google.com"
// || domain == "chat.alqatech.com"
{
let priority = DDXMLElement.elementWithName("priority", stringValue: "24") as! DDXMLElement
presence.addChild(priority)
}
xmppMUC = XMPPMUC(dispatchQueue: dispatch_get_main_queue())
xmppMUC!.activate(self.xmppStream)
xmppMUC!.addDelegate(self, delegateQueue: dispatch_get_main_queue())

xmppStream.sendElement(presence)
}


2. Create a group



func createGroupChat(members:[String],groupName:String){
membersToInvite = members
xmppRoomMemoryStorage = XMPPRoomMemoryStorage()
let xmppJid = XMPPJID.jidWithString("\(groupName)@conference.chat.xxxxxx.com")
let xmppRoom = XMPPRoom.init(roomStorage: xmppRoomMemoryStorage, jid: xmppJid)
xmppRoom.activate(xmppStream)
xmppRoom.addDelegate(self, delegateQueue: dispatch_get_main_queue())
xmppRoom.joinRoomUsingNickname(xmppStream.myJID.user, history: nil)
}


3. Group Created Successfully



func xmppRoomDidCreate(sender: XMPPRoom!) {
print(sender)
}


4. xmppRoomDidJoin called successfully then here i invite users



func xmppRoomDidJoin(sender: XMPPRoom!) {
sender.fetchConfigurationForm()
for JID in membersToInvite! {
sender.editRoomPrivileges([XMPPRoom.itemWithAffiliation("member", jid: XMPPJID.jidWithString(JID))])
sender.inviteUser(XMPPJID.jidWithString(JID), withMessage: "THIS IS GROUP MESSAGE")

}

}


5. didFetchConfigurationForm called successfully



func xmppRoom(sender: XMPPRoom!, didFetchConfigurationForm configForm: DDXMLElement!)
{

let newConfig: DDXMLElement = configForm.copy() as! DDXMLElement
let fields: [AnyObject] = newConfig.elementsForName("field")
for field in fields {
let vars: String = field.attributeStringValueForName("var")
// Make Room Persistent
if (vars == "muc#roomconfig_persistentroom") {
field.removeChildAtIndex(0)
field.addChild(DDXMLElement(name: "value", stringValue : "1"))
}
}
sender.configureRoomUsingOptions(newConfig)


}


6. didReceiveInvitation it is not being called.



func xmppMUC(sender: XMPPMUC!, roomJID: XMPPJID!, didReceiveInvitation message: XMPPMessage!) {
print(roomJID)
xmppRoomMemoryStorage = XMPPRoomMemoryStorage()
let xmppRoom = XMPPRoom.init(roomStorage: xmppRoomMemoryStorage, jid: roomJID)
xmppRoom.activate(xmppStream)
xmppRoom.addDelegate(self, delegateQueue: dispatch_get_main_queue())
xmppRoom.joinRoomUsingNickname(xmppStream.myJID.user, history: nil)

}

Answer

Problem was in this code. Actually i was sending the bare id every time when i was inviting any user.

func xmppRoomDidJoin(sender: XMPPRoom!) {
        sender.fetchConfigurationForm()
        for JID in membersToInvite! {
            sender.editRoomPrivileges([XMPPRoom.itemWithAffiliation("member", jid: XMPPJID.jidWithString(JID))])
            sender.inviteUser(XMPPJID.jidWithString(JID), withMessage: "THIS IS GROUP MESSAGE")

        }

    }

BUT TO INVITE ANY USER YOU HAVE TO USE FULL ID.

For those who dont know

BareID = username@domain FullID = username@domain/resource

To resolve this

I hardcode the resource = APPNAME everywhere in JIDs in whole app.