Shawn Mclean - 1 year ago 93

C# Question

I have 2 lines. Both lines containing their 2 points of X and Y. This means they both have length.

I see 2 formulas, one using determinants and one using normal algebra. Which would be the most efficient to calculate and what does the formula looks like?

I'm having a hard time using matrices in code.

This is what I have so far, can it be more efficient?

`public static Vector3 Intersect(Vector3 line1V1, Vector3 line1V2, Vector3 line2V1, Vector3 line2V2)`

{

//Line1

float A1 = line1V2.Y - line1V1.Y;

float B1 = line1V2.X - line1V1.X;

float C1 = A1*line1V1.X + B1*line1V1.Y;

//Line2

float A2 = line2V2.Y - line2V1.Y;

float B2 = line2V2.X - line2V1.X;

float C2 = A2 * line2V1.X + B2 * line2V1.Y;

float det = A1*B2 - A2*B1;

if (det == 0)

{

return null;//parallel lines

}

else

{

float x = (B2*C1 - B1*C2)/det;

float y = (A1 * C2 - A2 * C1) / det;

return new Vector3(x,y,0);

}

}

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Assuming you have two lines of the form `Ax + By = C`

, you can find it pretty easily:

```
float delta = A1*B2 - A2*B1;
if(delta == 0)
throw new ArgumentException("Lines are parallel");
float x = (B2*C1 - B1*C2)/delta;
float y = (A1*C2 - A2*C1)/delta;
```

Pulled from here

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**