johndir - 9 months ago 66

Python Question

`a = [1, 2, 3, 1, 2, 3]`

b = [3, 2, 1, 3, 2, 1]

a & b should be considered equal, because they have exactly the same elements, only in different order.

The thing is, my actual lists will consist of objects (my class instances), not integers.

Answer

**O(n)**: The *Counter()* method is best (if your objects are hashable):

```
def compare(s, t):
return Counter(s) == Counter(t)
```

**O(n log n)**: The *sorted()* method is next best (if your objects are orderable):

```
def compare(s, t):
return sorted(s) == sorted(t)
```

**O(n * n)**: If the objects are neither hashable, nor orderable, you can use equality:

```
def compare(s, t):
t = list(t) # make a mutable copy
try:
for elem in s:
t.remove(elem)
except ValueError:
return False
return not t
```

Source (Stackoverflow)