hari hari - 5 months ago 27
Perl Question

String compare in Perl with "eq" vs "=="

I am (a complete Perl newbie) doing string compare in an

if
statement:

If I do following:

if ($str1 == "taste" && $str2 == "waste") { }


I see the correct result (i.e. if the condition matches, it evaluates the "then" block). But I see these warnings:


Argument "taste" isn't numeric in numeric eq (==) at line number x.

Argument "waste" isn't numeric in numeric eq (==) at line number x.


But if I do:

if ($str1 eq "taste" && $str2 eq "waste") { }


Even if the if condition is satisfied, it doesn't evaluate the "then" block.

Here,
$str1
is
taste
and
$str2
is
waste
.

How should I fix this?

Answer

First, eq is for comparing strings; == is for comparing numbers.

Even if the "if" condition is satisfied, it doesn't evaluate the "then" block.

I think your problem is that your variables don't contain what you think they do. I think your $str1 or $str2 contains something like "taste\n" or so. Check them by printing before your if: print "str1='$str1'\n";.

The trailing newline can be removed with the chomp($str1); function.