gwiz_kid - 1 year ago 66
C Question

# Else if option 3 does not produce answer...what did I do wrong?

The program runs but I can't figure out why the function within the third
else if statement doesn't return an accurate value. Thank you for the help in

``````finaltemp = newtemp(t, choice);

printf("\nThe converted temperature is: %f", finaltemp);

return(0);
}

double newtemp(double a, double b)
{
double result;
if (b==1)
{
result = (a-(273.15));
}
if (b==2)
{
result = (a+(273.15));
}
if (b==3)
{
result = (((5/9)*(a))-32);
}
if (b==4)
{
result = (((9/5)*(a))+32);
}
if (b==5)
{
result = (((9/5)*(a))-459.67);
}
if (b==6)
{
result = ((a+459.67)*(9/5));
}

return(result);
}
``````

You're performing integer division, not floating point division.

The expression `(5/9)` divides two `int` values, so the result is an `int`, specifically 0. You need to use floating point constants to force floating point division.

``````if (b==3)
{
result = (((5.0/9.0)*(a))-32);
}
if (b==4)
{
result = (((9.0/5.0)*(a))+32);
}
if (b==5)
{
result = (((9.0/5.0)*(a))-459.67);
}
if (b==6)
{
result = ((a+459.67)*(9.0/5.0));
}
``````
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