Nathan Fellman Nathan Fellman - 9 months ago 50
Python Question

How can I handle exceptions in a list comprehension in Python?

I have some a list comprehension in Python in which each iteration can throw an exception.

For instance, if I have:

eggs = (1,3,0,3,2)

[1/egg for egg in eggs]

I'll get a
exception in the 3rd element.

How can I handle this exception and continue execution of the list comprehension?

The only way I can think of is to use a helper function:

def spam(egg):
return 1/egg
except ZeroDivisionError:
# handle division by zero error
# leave empty for now

But this looks a bit cumbersome to me.

Is there a better way to do this in Python?

Note: This is a simple example (see "for instance" above) that I contrived because my real example requires some context. I'm not interested in avoiding divide by zero errors but in handling exceptions in a list comprehension.

Answer Source

There is no built-in expression in Python that lets you ignore an exception (or return alternate values &c in case of exceptions), so it's impossible, literally speaking, to "handle exceptions in a list comprehension" because a list comprehension is an expression containing other expression, nothing more (i.e., no statements, and only statements can catch/ignore/handle exceptions).

Function calls are expression, and the function bodies can include all the statements you want, so delegating the evaluation of the exception-prone sub-expression to a function, as you've noticed, is one feasible workaround (others, when feasible, are checks on values that might provoke exceptions, as also suggested in other answers).

The correct responses to the question "how to handle exceptions in a list comprehension" are all expressing part of all of this truth: 1) literally, i.e. lexically IN the comprehension itself, you can't; 2) practically, you delegate the job to a function or check for error prone values when that's feasible. Your repeated claim that this is not an answer is thus unfounded.