Aria Aria - 29 days ago 19
C# Question

Multiple file in one Stream, custom stream

According to the answer here I want to write multiple files stream to one stream as following:

4 byte reserved for length number of each stream
each stream content write after it's length number(after 4 byte)
at the end stream will be something like this

Stream =

File1 len + File1 stream content + File2 len + File2 stream content + ....


Example code:

result = new ExportResult_C()
{
PackedStudy = packed.ToArray() ,
Stream = new MemoryStream()
};
string[] zipFiles = Directory.GetFiles(zipRoot);
foreach (string fileN in zipFiles)
{
MemoryStream outFile = new MemoryStream(File.ReadAllBytes(fileN));
MemoryStream len = new MemoryStream(4);
//initiate outFile len to 4 byte push it to main stream
//Then push outFile stream to main stream
//Continue and do this for another file
}
//For test Save stream to file(s)


is it good idea? really don't know how that comments can be lines of code.

Thanks in advance.

Answer

Try this

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            byte[] testMessage = Encoding.UTF8.GetBytes("The quick brown fox jumped over the lazy dog");
            MemoryStream outFile = new MemoryStream();
            BinaryWriter writer = new BinaryWriter(outFile);
            for (int i = 0; i < 10; i++ )
            {
                writer.Write(BitConverter.GetBytes(testMessage.Length), 0, 4);
                writer.Write(testMessage, 0, testMessage.Length);
            }
            writer.Flush();

            outFile.Position = 0;
            BinaryReader reader = new BinaryReader(outFile, Encoding.UTF8);
            while (outFile.Position < outFile.Length)
            {
                int size = reader.ReadInt32();
                byte[] data = reader.ReadBytes(size);
            }
        }
    }
}
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