dustin - 1 year ago 242

Python Question

I have looked through scipy.integrate.ode but I am unable to find out how to actually use these integration methods,

`dorpi5`

`dop853`

I would like to try integrating ode integration python versus mathematica my python code with these two methods to see how it effects the results but don't know how.

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Answer Source

You call the method `set_integrator`

on the `ode`

class with either `'dopri5'`

or `'dop853'`

as its argument.

Here's an example:

```
import numpy as np
import matplotlib.pyplot as plt
from scipy.integrate import ode
def fun(t, z, omega):
"""
Right hand side of the differential equations
dx/dt = -omega * y
dy/dt = omega * x
"""
x, y = z
f = [-omega*y, omega*x]
return f
# Create an `ode` instance to solve the system of differential
# equations defined by `fun`, and set the solver method to 'dop853'.
solver = ode(fun)
solver.set_integrator('dop853')
# Give the value of omega to the solver. This is passed to
# `fun` when the solver calls it.
omega = 2 * np.pi
solver.set_f_params(omega)
# Set the initial value z(0) = z0.
t0 = 0.0
z0 = [1, -0.25]
solver.set_initial_value(z0, t0)
# Create the array `t` of time values at which to compute
# the solution, and create an array to hold the solution.
# Put the initial value in the solution array.
t1 = 2.5
N = 75
t = np.linspace(t0, t1, N)
sol = np.empty((N, 2))
sol[0] = z0
# Repeatedly call the `integrate` method to advance the
# solution to time t[k], and save the solution in sol[k].
k = 1
while solver.successful() and solver.t < t1:
solver.integrate(t[k])
sol[k] = solver.y
k += 1
# Plot the solution...
plt.plot(t, sol[:,0], label='x')
plt.plot(t, sol[:,1], label='y')
plt.xlabel('t')
plt.grid(True)
plt.legend()
plt.show()
```

This generates the following plot:

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